Wallpapercsuy

Dy / dx P (x) y = Q (x) where P (x) and Q (x) are functions of x If we multiply all terms in the differential equation given above by an unknown function u (x), the equation becomes u (x) dy / dx u (x) P (x) y = u (x) Q (x)Observe that according to Euler's totient formula, let a be any integer coprime to p, then (a, p) = 1 Then a^ (phi (p)) â ¡ 1 (mod p) Now since p is prime, all a in Z/PZ is coprime to p and phi (p) = (p1) Then (xy)^p = (xy) (xy)^ (p1) (mod p) â ¡ (xy) (1) (mod p)It seems that there's tendency to agree upon p (x)⇒∀xp (x) is the same as ∀x (p (x)⇒∀yp (y)), whereas ∀x (p (x)⇒∀yp (y)) is read as if p (x) is true for some x, then it is true for all x However I don't understand where's the quantifier SOME came from, since there no quantifier '∃' in '∀x (p (x)⇒∀yp (y))' Complete Parts A Through F Below To Find Nonnegative Numbers X And Y That Satisfy The Homeworklib P(x y) calculator